How to relate an array of integers to an array of strings in the code?

Question

I'm a Python beginner who is starting to get familiar with the pymc library. In my program I'm generating random numbers between 1 and 100. When I'm generating random variables, it obviously returns an array with integers (in this case a 10 int array):

customer_names = customer_names.random(size=10)

The history of this post is that I want to relate each int variable to a specific name through a table, as if each name had an identifier, but I don't know how to implement it in the code.

What I want is that when I print(customer_names) instead of getting an array [ 54 2 45 75 22 19 16 34 67 88] I want to get [ Jose Maria Carmen Alejandro Davinia Eduardo Carlos Fátima Marc Mireia].

I have tried the following:

def identificar_nombres(nc = customer_names):
    for i in range (0, 9): #in this case 9 because I'm generating 10 random numbers
        if nc[i] == '1':
            return 'ANTONIO' 
        elif nc[i] == '2':
            return 'MARIA CARMEN'
        else: return nc[i] # process repeatedly with all names in the name dataset

nombres = identificar_nombres(customer_names)

but without result.

Thanks!

What you can do create a dictionary of names like this dictionary = {"1": 'ANTONIO', "2": "MARIA CARMEN"} etc. and then access the names from the dictionary using dictionary[str(nc[i)] — Rishabh Batra
– Rishabh Batra, Commented Feb 25, 2020 at 15:05
@RishabhBatra Thankyou so much, another stupid thing, how can transform an array of random numbers, to an array transformed by the dictionary with the names ? — EduardoCabria
– EduardoCabria, Commented Feb 25, 2020 at 16:34

Suman Niroula · Accepted Answer · 2020-02-25 15:19:23Z

0

Use a dictionary(key-value pair) to store the variables like this:

variables = {1: 'ANTONIO', 2: 'MARIA CARMEN'}

And access it like this:

customer_names = list(variables.values()))
print(customer_names)

Output:

['ANTONIO', 'MARIA CARMEN']

answered Feb 25, 2020 at 15:19

Suman Niroula

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2 Comments

EduardoCabria Over a year ago

Thankyou so much Suman, only another stupid doubt, but if I have an array of integers with 10 random numbers, we can call it 'array_indicators'. How can I transform, using that dictionary, that array to another called 'names array' with the values of the dictionary (in this case, the 'values' are the names)

EduardoCabria Over a year ago

I found it, problem fixed ;)

Basu_C · Accepted Answer · 2020-02-25 15:22:14Z

0

By "without result", I am assuming you are getting the else statement.

This is because using if nc[i] == '1' you are comparing class 'int' to class 'str' which will never match. Try the following code:

if nc[i] == 1:
            return 'ANTONIO'

Alternatively, using dictionary(key-value) will be a better approach here.

answered Feb 25, 2020 at 15:22

Basu_C

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Comments

sirdoug9 · Accepted Answer · 2020-02-25 15:23:15Z

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def identificar_nombres(customer_names):
  customerlist = []
  for i in customer_names:
      if customer_names[i] == 1:
          customerlist.append("ANTONIO") 
      elif customer_names[i] == 2:
          customerlist.append("MARIA")
  return customerlist

nombres = identificar_nombres(customer_names) 
print(nombres)

answered Feb 25, 2020 at 15:23

sirdoug9

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