Python condition if/else invalid syntax

Question

Hi, can you help me with the following error? I know it sounds very stupid. When doing an if / else conditional, I get a syntax error. Would appreciate your help.

 def request(self, email, password):
   session = requests.session()
   login_page = session.get(login_url)
   login_soup = BeautifulSoup(login_page.text,'html5lib' )
   e = login_soup.find('input', {'name':'login_form[_token]'})
   csrftok = e['value']
   session.post(login_url,data={'login_form[name]': user,'login_form[password]': passw,'login_form[redirect_url]': '/','login_form[_token]': csrftok})
   membership = session.get(member_url).text()
   if "Free" in membership:
       output().screen(email, password, case = "Free")
       else:
           output().screen(email, password, case = "Premium")
   else:
       output().screen(email, password, case = "Not Working")

It looks like you'll need to learn about elif to achieve the behaviour you're interested in here — byxor
– byxor, Commented Nov 12, 2019 at 13:52

vauhochzett · Accepted Answer · 2019-11-12 16:45:50Z

2

The third line here...

if "Free" in membership:
    output().screen(email, password, case = "Free")
    else:  # <----- Problematic line
        output().screen(email, password, case = "Premium")
else:
    output().screen(email, password, case = "Not Working")

has no corresponding if statement. You need another if statement, otherwise remove that line.

edited Nov 12, 2019 at 16:45

vauhochzett

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answered Nov 12, 2019 at 13:52

Fruity Medley

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1 Comment

Zoma Over a year ago

I guess what the OP is trying to do is an "else if", you may include an example to show how it should be done.

Elpedio Jr. Adoptante · Accepted Answer · 2019-11-12 14:10:52Z

1

I guess you want to do if elif else

if "Free" in membership:
   output().screen(email, password, case="Free")
elif "Premium" in membership:
   output().screen(email, password, case="Premium")
else:
   output().screen(email, password, case="Not Working")

answered Nov 12, 2019 at 14:10

Elpedio Jr. Adoptante

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Comments

Andy Lukito · Accepted Answer · 2019-11-12 14:14:24Z

0

if "Free" in membership:
   output().screen(email, password, case = "Free")
>>>else:
       output().screen(email, password, case = "Premium")
else:
       output().screen(email, password, case = "Not Working")

Indentation
There is a stray 'else'

answered Nov 12, 2019 at 14:14

Andy Lukito

1

Comments

SOF · Accepted Answer · 2019-11-12 14:14:27Z

In python it is really important to respect indentation and to have a well organized code. As you have an else statement without an if And for {{else if}} you can use elif So you have to follow the following pattern:

if c:
   code
elif c1:
   code1
else:
   code2

so your code has to be like this:

 def request(self, email, password):
   session = requests.session()
   login_page = session.get(login_url)
   login_soup = BeautifulSoup(login_page.text,'html5lib' )
   e = login_soup.find('input', {'name':'login_form[_token]'})
   csrftok = e['value']
   session.post(login_url,data={'login_form[name]': user,'login_form[password]': passw,'login_form[redirect_url]': '/','login_form[_token]': csrftok})
   membership = session.get(member_url).text()
   if "Free" in membership:
       if <<condition here>>:
           output().screen(email, password, case = "Free")
       else:
           output().screen(email, password, case = "Premium")
   else:
       output().screen(email, password, case = "Not Working")

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