python If statement Syntax error? [duplicate]

Question

new to python, currently reading diveintopython and trying to run the following code from the book:

def buildConnectionString(params):
   """Build a connection string from a dictionary of parameters.

      Returns string."""
      return ";".join(["%s=%s" % (k, v) for k, v in params.items()])
if __name__ == "__main__":
      myParams = {"server":"mpilgrim", \
                  "database":"master", \
                  "uid":"sa", \
                  "pwd":"secret" \
                  }
    print buildConnectionString(myParams)

Now when i hit enter, Python shell says the if statement has a syntax error?? I'm running Python 2.7.

Welcome to StackOverflow. posting the (full and exact) error you get will let people help you faster :) — MByD
– MByD, Commented Dec 19, 2011 at 9:16
this indentation stuff is driving me crazy. can someone suggest me a editor to use? i'm baffled of why i cant print this statement with these indentation errors — Apprentice Programmer
– Apprentice Programmer, Commented Dec 19, 2011 at 19:54

Sonya · Accepted Answer · 2011-12-19 09:22:52Z

3

The code itself is working (I just tried it). A possible reason for errors is inconsistent indentation. It seems that your lines start with different numbers of spaces (or tabs). Try changing the the blank space in the beginning of each indented line to, say, four spaces, and try running the script again.

answered Dec 19, 2011 at 9:22

Sonya

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2 Comments

Apprentice Programmer Over a year ago

what environment do you use to code in? sorry i'm new and lost that people are telling me not to code in the shell? where am i supposed to code then?

Sonya Over a year ago

@Apprentice Programmer: I usually use Python IDLE or Geany.

Daniel Roseman · Accepted Answer · 2011-12-19 09:34:43Z

2

The error is in line 5: the return should be indented at the level of the opening """ of the function.

However, you shouldn't be entering that code in the shell - do it in a text editor.

answered Dec 19, 2011 at 9:34

Daniel Roseman

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Comments

Achim · Accepted Answer · 2011-12-19 09:21:13Z

0

Looks like your indentation levels are wrong. Looking at your pasted code, I would guess that you are mixing tabs and blanks, so you are using a "bad" editor. Use an editor which replaces tabs by blanks.

answered Dec 19, 2011 at 9:21

Achim

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Zeeking786 · Accepted Answer · 2021-01-17 15:42:14Z

0

I have solved your issue and i am uploading the proper syntax of code

def buildConnectionString(params):
   return ";".join(["%s=%s" % (k, v) for k, v in params.items()])
if __name__ == "__main__":
    myParams = {"server":"mpilgrim", \
                  "database":"master", \
                  "uid":"sa", \
                  "pwd":"secret" \
                }
print (buildConnectionString(myParams))

I hope this will helpful as well as useful for you !!

answered Jan 17, 2021 at 15:42

Zeeking786

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