ES6 array destructuring for specific index [duplicate]

Question

I have an Array const arr = new Array(100).

And I set

arr[0] = 'A'
arr[49] = 'X'

When destructuring the 1st element, I can do it like:

let [first] = arr

How the statement would be like if I want to access to the 50th element by destructuring expression?

I know, but you wouldn't use destructuring to get the 50th element @NullDev — baao
– baao, Commented May 17, 2019 at 8:30
I ran into the issue because ESLint notifies me to use destructuring while I am going to use let key = arr[3]. — LiuWenbin_NO.
– LiuWenbin_NO., Commented May 17, 2019 at 8:44

Kobe · Accepted Answer · 2022-01-19 08:39:38Z

14

You can grab the element using object destructuring, like so:

const arr = Array(50).fill(0).map((_, i) => `Element ${i + 1}`)

const {49: fifty} = arr
console.log(fifty)

answered May 17, 2019 at 8:29

Kobe

6,4681 gold badge18 silver badges38 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

can the index by dynamic?

@capr Can you be more specific? Destructuring like this isn't common, just use bracket notation like arr[index].