xslt variable with xml structure

Question

I need to get into a variable the internal structure of a node, the issue is that the node has different paths by different reasons. What I am doing until now is

<xsl:variable name="my_variable">
  <xsl:choose>
    <xsl:when test="One/Path/To/TheNode">
      <xsl:value-of select="One/Path/To/TheNode"/>
    </xsl:when>
    <xsl:when test="One/Different/Path/To/TheNode">
      <xsl:value-of select="One/Different/Path/To/TheNode"/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="//TheNode"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:variable>

And then if I use this variable to get some subnode doing:

   <xsl:variable name="other_variable" select="$my_variable/Subnode"/>

I get this error in runtime XPath error : Invalid type Evaluating global variable var/param being computed failed, I tried too doing this:

<xsl:variable name="other_variable" select="ext:node-set($my_variable)/SubNode"/>

I don´t get any error executing the xslt, but other_variable is empty. Checking the content of my_variable doing <xsl:value-of select="$my_variable"/> or <xsl:apply-templates mode="copy" select="ext:node-set($my_variable)"/> I can see the data but without the xml structure, I mean I can see bar but not <foo>bar</bar>.

Is there any way to get this structure from a different path without use <xsl:variable name="my_variable" select="//TheNode"/>??

Thanks.

woohhoo!!! Thanks @michael.hor257k it worked. I had tried with copy but I didn´t think copy-of. Please, add as an answer and I´ll accept it. Thanks!! — Eloy Fernández Franco
– Eloy Fernández Franco, Commented Apr 3, 2019 at 9:32

michael.hor257k · Accepted Answer · 2019-04-03 09:39:07Z

1

The xsl:value-of instruction will create a text node with the string-value of the selected node - or more precisely, the first node of the selected node-set (in XSLT 1.0).

If you want to preserve the structure, use the xsl:copy-of instruction instead.

answered Apr 3, 2019 at 9:39

michael.hor257k

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