PHP Image from URL

Question

I have the following url which returns an image in the body, How would I assign that image to a variable so that I could save it or use it within my code?

https://media.licdn.com/dms/image/C4E03AQGOM3p0fHNkwQ/profile-displayphoto-shrink_100_100/0?e=1556755200&v=beta&t=qeQFKYXpev2ZW3hmP1ODDPd3DYPWvl-GaUnPSZG-aQA

The following code returns noting:

<?php
     $url = "https://media.licdn.com/dms/image/C4E03AQGOM3p0fHNkwQ/profile-displayphoto-shrink_100_100/0?e=1556755200&v=beta&t=qeQFKYXpev2ZW3hmP1ODDPd3DYPWvl-GaUnPSZG-aQA";
     $image = file_get_contents($url);
     echo $image;
?>

How would I assign that image to a variable so that I could save it or use it within my code --- you already did. — specializt
– specializt, Commented Feb 28, 2019 at 14:48
Such a CDN might reject requests it does not think come from a “regular” browser … so I’d start with specifying a User-Agent request header that mimics that of a current, popular browser. (If you don’t know how to do that using file_get_contents, please research.) — 04FS
– 04FS, Commented Feb 28, 2019 at 14:50
Possible duplicate of php: recreate and display an image from binary data — Motassem Kassab
– Motassem Kassab, Commented Feb 28, 2019 at 14:54

Motassem Kassab · Accepted Answer · 2019-02-28 15:09:48Z

2

If you simply want to view an image from a URL, just put that url in the src attribute of an img element like this :
echo '<img src="' . $url . '"/>';

otherwise, if you have to view it from the fetched data of that url, then your question have been answered here:
php: recreate and display an image from binary data (specifically @Krab's answer)

edited Feb 28, 2019 at 15:09

answered Feb 28, 2019 at 14:56

Motassem Kassab

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