Type Casting an Decoded Json Object to array, generate error while accessing it

Question

I decoded a json string and then Type casted it into any Array and tried to access it later. But it generate Undefined Index Error

Here is my sample code

$json = '{"1":"Active","0":"Inactive"}'; //Yes, it is a valid Json String
$decodedObject = json_decode($json);
$array = (array)$decodedObject;
echo $array['1']; // This generates undefinded Index 1 Error

Here is the display of the array and object

stdClass Object
(
    [1] => Active
    [0] => Inactive
)

Array
(
    [1] => Active
    [0] => Inactive
)

Just do var_dump with $array and look what you've got.

xappymah
– xappymah

2011-03-27 08:26:18 +00:00
Commented Mar 27, 2011 at 8:26 — xappymah
– xappymah, Commented Mar 27, 2011 at 8:26

KoolKabin · Accepted Answer · 2011-03-27 08:24:17Z

1

1.) instead of making it in two steps how about doing it like:

$decodedArray = json_decode($json, true);

it will directly give you the array instead of object

2.) make sure your json code is corret:

{"1":"Active","0":"Inactive"}

3.) your var_dump shows that array{[1]=>.... so why refering it like $array['1'] can it be even simpler $array[1]

answered Mar 27, 2011 at 8:24

KoolKabin

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1 Comment

mrN Over a year ago

wow, this fixed everything. I will accept it in five minute :D Thanks

ThiefMaster · Accepted Answer · 2011-03-27 08:22:28Z

1

No, it is not a valid JSON string (JSONLint is your friend). You used a comma instead of a colon:

{"1":"Active","0","Inactive"} // invalid
{"1":"Active","0":"Inactive"} // valid

answered Mar 27, 2011 at 8:22

ThiefMaster

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