Format entries in list to 8 bit binary in python

Question

I have a list A = [100011, 1110110]. I want to make each entry in the list 8 bit using the format option:

B = '{0:08b}'.format(A[1])
B = '{0:08b}'.format(A[2])

But when I print(B). I am getting the output as: B = 100001111000001011110 and B = 11000011010101011

Why is this happening? Is this command not used for list?

blhsing · Accepted Answer · 2018-12-17 19:17:31Z

2

The integer literals defined in the list A are specified in decimals. You should specify them as binary literals (prefixed with 0b) instead:

A = [0b100011, 0b1110110]
print('{0:08b}'.format(A[0]))
print('{0:08b}'.format(A[1]))

This outputs:

00100011
01110110

answered Dec 17, 2018 at 19:17

blhsing

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2 Comments

As with all formatting options, if the result doesn't fit in the specified length the length is expanded. Good catch on the constants.

@MarkRansom Thank you. That helped.