0

In this code 

N = 4
M = 30

# Generar datos a partir de 3 clusters diferentes:

X1 = 10 + 2*np.random.randn(M/3,N)
X2 = -10 + 5*np.random.randn(M/3,N) 
X3 = 1*np.random.randn(M/3,N)

I get this error

Traceback (most recent call last):
  File "/home/user/PycharmProjects/tema3/3.18_MDS.py", line 16, in <module>
    X1 = 10 + 2*int(np.random.randn(M/3,N)) # cluster 1 (dispersion media)
  File "mtrand.pyx", line 1420, in mtrand.RandomState.randn
  File "mtrand.pyx", line 1550, in mtrand.RandomState.standard_normal
  File "mtrand.pyx", line 167, in mtrand.cont0_array
TypeError: 'float' object cannot be interpreted as an integer

I'm not sure about the problem because I think I'm not pasing any float to randn.

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  • python3 i presume? try looking at the output of print(M/3) Commented Apr 2, 2018 at 17:19
  • yes it is python3 Commented Apr 2, 2018 at 17:20
  • 1
    integer division in python 3 returns a float. If you want to truncate (as python2 did) you need to use //. Try replacing M/3 with M//3 everywhere. Commented Apr 2, 2018 at 17:21
  • 1
    Even though this is a dupe, and OP should have tried debugging the program with a few print statements, I think the downvotes here are a little harsh. The change in behavior of the / operator is not obvious. Commented Apr 2, 2018 at 17:28
  • @pault It's not the change in behavior of / that's the problem, it's numpy not accepting 30/3 = 10.0 as an integer (even though it is an integer) Commented Mar 6, 2021 at 16:12

1 Answer 1

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3

In Python3 integer division with / returns a float. You need to use // to get an integer (rounded down).

>>> type(1)
<class 'int'>

>>> type(1/1)
<class 'float'>

>>> type(1//1)
<class 'int'>

>>> 1/2
0.5

>>> 1//2
0
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