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Currently the following error occurs. I believe the problem is due to this code been written for python 2.X and not working in my current version of python 3.8.3

self.zz=np.zeros(self.nhalf,'f') TypeError: 'float' object cannot be interpreted as an integer

References to self.zz and self.nhalf in the program are shown below

self.nhalf=0
self.nhalf=self.num_fft/2

self.zz=[]
self.zz=self.zz[n1:n2]

I wonder is there simple adjustment required to remove the error?

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  • 1
    From numpy docs: numpy.zeros(shape, dtype=float, order='C') shape : int or tuple of ints -- / returns a float... Commented Dec 3, 2020 at 11:50
  • 2
    Since Python 3.5(I think) the / operator does regular division, meaning the result could be a float. If you want floor division, you can use the // operator. Commented Dec 3, 2020 at 11:51
  • @jaaq correction: meaning the result is always a float Commented Dec 3, 2020 at 11:52
  • @Tomerikoo oh you're right! I never bothered to try type(4/2). Thanks, learned something new :) Commented Dec 3, 2020 at 11:55
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    @jaaq No need. The result of 4/2 is 2.0 which gives a hint of its type ^_^ Commented Dec 3, 2020 at 11:56

1 Answer 1

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I am pretty sure that the problem is that Python2 did integer division by default while Python3.5(ish) started using regular division.

I think your error means that you are trying to create a numpy array with e.g. 17.5 zeros in it, which obviously doesn't work.

Try replacing the / operator with the // floor division operator:

self.nhalf=self.num_fft//2
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