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This is my matrix in R:

n_forward=50

matriz=matrix(0,nrow=length(1:n_forward),ncol=16)

The number of rows depends of n_forward command.

from there I want to name de rows with this legends: t+1, t+2,....,t+(n_forward)

Is there any way to do this automatically, without having to do this below?

rownames(matriz)<-c("t+1","t+2","t+3","t+4","t+5","t+6","t+7","t+8","t+9","t+10","t+11","t+12","t+13","t+14","t+15","t+16","t+17","t+18","t+19","t+20","t+21","t+22","t+23","t+24","t+25","t+26","t+27","t+28","t+29","t+30", "t+31","t+32","t+33","t+34","t+35","t+36","t+37","t+38","t+39","t+40","t+41","t+42","t+43","t+44","t+45","t+46","t+47","t+48","t+49","t+50")
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  • like this: n_forward=101 matriz=matrix(0,nrow=length(1:n_forward),ncol=16) rownames(matriz)<-paste0("t+", 1:length(n_forward)) ? Commented Nov 1, 2017 at 14:11
  • Thanks! It works now. I will edit the code. n_forward=1:101 matriz=matrix(0,nrow=length(n_forward),ncol=16) rownames(matriz)<-paste0("t+", 1:length(n_forward)) Commented Nov 1, 2017 at 14:15
  • 1
    If you run length(n_forward) it returns 1. Instead you need to omit the length function. So, rownames(matriz)<- paste0("t+", 1:n_forward) should work. Commented Nov 1, 2017 at 14:15
  • 1
    So which code worked, mine or that from @DiogoBastos ? Commented Nov 1, 2017 at 14:18
  • 4
    If n_forward could ever be 0, then seq_len(n_forward) is safer than 1:n_forward. The first would return an empty vector, the second would return c(1, 0). Commented Nov 1, 2017 at 14:19

1 Answer 1

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1

What you need is this:

n_forward=50
matriz=matrix(0,nrow=length(1:n_forward),ncol=16)
rownames(matriz)<-paste0("t+",1:n_forward)
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