Node.JS - Call a Pre-Defined Function in Another Function

Question

I have a function, functionOne, defined normally, outside of other functions or if statements. Now I have another function, functionTwo, and I call functionOne inside of functionTwo. I've tried searching around but I could only find things that told me to define functionOne inside of functionTwo. My issue is that it's already defined, outside of any functions, as I said before.

Here's my code:

function functionOne (connection) {
//code here for functionOne
}

function functionTwo (functionOne, connection) {
//some code here for functionTwo

functionOne(connection)
}

The error is that the connection var isn't being passed over. Any fixes appreciated! Thanks :)

you aren't defining functions correctly. should be: function <functionName> () {} — hackerrdave
– hackerrdave, Commented Oct 28, 2017 at 16:07
@hackerrdave sorry I messed up in the question, I did actually do that I just forgot to add it there my bad :P — APixel Visuals
– APixel Visuals, Commented Oct 28, 2017 at 16:34
what do you mean by "connection var isn't being passed over"? how are you invoking functionTwo ? — hackerrdave
– hackerrdave, Commented Oct 28, 2017 at 16:47
@hackerrdave OHHHHH I didn't pass functionOne as a parameter when invoking functionTwo.... hehe got it fixed now thanks :P — APixel Visuals
– APixel Visuals, Commented Oct 28, 2017 at 16:53

ganjim · Accepted Answer · 2017-10-28 16:03:38Z

1

to define a function you should use this syntax:

function funcName(args){
    //code
}

here in your example you did not define any function. you just called functions that don't exist.

answered Oct 28, 2017 at 16:03

ganjim

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3 Comments

APixel Visuals Over a year ago

sorry I messed up in the question, I did actually do that I just forgot to add it there my bad :P

ganjim Over a year ago

then you don't need to pass functionOne as an argument to functionTwo

APixel Visuals Over a year ago

Thanks but I've already got it figured out in the comments of the original question :)

Taylor O'Reilly · Accepted Answer · 2017-10-28 17:29:00Z

0

If I am understanding your question you just need to provide the argument(s) for the first function within in the second

   function funcOne(a){
    return a
}

function funcTwo(b, c){
    //funcTwo's value of "b" will be used for funcOne as the "a" argument
    return funcOne(b) + c
}

console.log(funcTwo(3,4)) //returns 7

answered Oct 28, 2017 at 17:29

Taylor O'Reilly

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