change the value of a multidimentional dict in python with nested dict enclosed in a list

Question

for example, let's say i have a dict like this:

bulk_details={
    "ad":'ad',
    'ad':[
        {'ad':'ad'},
        {'ad':'ad'}
    ]
}

I want to encrypt the values in the dict. i'm stuck at parsing the inner dicts inside the list

my code is this:

new_data = {key: {key_: encrypt(val_) for key_, val_ in (val.items() if type(val) is dict else val)} for key, val in (bulk_details.items() if type(bulk_details) is dict else bulk_details) }

@SachinKukreja The same structure but with all dict values encrypted I guess. — Ma0
– Ma0, Commented Oct 27, 2017 at 8:35
Will you be able to read and understand your code in two days? Huge one-liners are satisfying in the very-short run, but they are bad code (in terms of maintainability). — Reut Sharabani
– Reut Sharabani, Commented Oct 27, 2017 at 8:40
Yes my frist reaction was that although it may seem "pythonic" to make that encryption a 1-liner, its not easy to understand, which makes it then not "pythonic". — jeffery_the_wind
– jeffery_the_wind, Commented Oct 27, 2017 at 8:41
Exactly, "one-liner" is not a pythonic property. Its just that often one-liners are very clear in python, and that makes them "pythonic". — Reut Sharabani
– Reut Sharabani, Commented Oct 27, 2017 at 8:49

Lukas Ansteeg · Accepted Answer · 2017-10-27 08:55:14Z

4

This is not nearly as compact as your one-liner, but it solves your problem and you can perhaps make it more compact:

bulk_details = {
    'ad':'ad',
    'ad2':
        [
            {'ad':'ad'},
            {'ad':'ad'}
        ]
}

def encrypt(to_encrypt):
    return '?' + to_encrypt + '?'

def encrypt_nested(dt):
    if isinstance(dt, dict):
        for key, value in dt.items():
            if isinstance(value, str):
                dt[key] = encrypt(value)
            else:
                encrypt_nested(value)
        return dt
    else: # elif isinstance(dt, list)
        for value in dt:
            if isinstance(value, str):
                value = encrypt(value)
            else:
                encrypt_nested(value)
        return dt

print(encrypt_nested(bulk_details))
# {'ad': '?ad?', 'ad2': [{'ad': '?ad?'}, {'ad': '?ad?'}]}

It iterates through a nested dict including arrays for any amount of levels using a recursing function.

answered Oct 27, 2017 at 8:55

Lukas Ansteeg

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1 Comment

dastiv21 Over a year ago

Thanks. That fix my problem

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