Unable to take multiple String input using scanner in java

Question

I have been trying to do a program in which i have to concat three strings in java.I am taking input from user using Scanner.It compiles perfect but when i run it,it gives me this error:

Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:864)
    at java.util.Scanner.next(Scanner.java:1485)
    at java.util.Scanner.nextInt(Scanner.java:2117)
    at java.util.Scanner.nextInt(Scanner.java:2076)
    at Night.main(Night.java:10)

This is my code:

import java.lang.*;
import java.util.*;

class Demo {
	public static void main(String[] args) {
		String fn;
		String mn;
		String ln;
		String fmn, lmn;
		Scanner sc = new Scanner(System.in);
		fn = sc.nextLine();
		mn = sc.nextLine();
		ln = sc.nextLine();
		fmn = fn.concat(mn);
		lmn = fmn.concat(ln);
		System.out.println("The Full name of candidate is : " + lmn);
	}
}

Supun Amarasinghe · Accepted Answer · 2017-08-18 04:54:52Z

2

Your code works fine. Remove the [] near class declaration.

class VecDemo
{

public static void main(String[] args)
{
    String fn;
    String mn;
    String ln;
    String fmn,lmn;
    Scanner sc = new Scanner(System.in);
    fn=sc.nextLine();
    mn=sc.nextLine();
    ln=sc.nextLine();
    fmn=fn.concat(mn);
    lmn=fmn.concat(ln);
    System.out.println("The Full name of candidate is : " + lmn);
}
}

Refer the attachment.

edited Aug 18, 2017 at 4:54

answered Aug 18, 2017 at 4:40

Supun Amarasinghe

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Comments

Kenny Tai Huynh · Accepted Answer · 2017-08-18 04:58:52Z

1

I believe your current code in Demo class is working fine. Can you check again?! The exception is from Night.main(Night.java:10). If you still have the same error, can you check if there is any Night class in your working space?!

Hope this help.

answered Aug 18, 2017 at 4:58

Kenny Tai Huynh

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2 Comments

Mr_Null_Byte Over a year ago

It Worked guys.It was just a silly mistake ,I Saved the program by name "Night.java" though my class name was VecDemo. Thank you All members for your help..Highly appreciated

Kenny Tai Huynh Over a year ago

Haha. That's fine. :)

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