In my system,i need to add 2 Hexa values.So, how can i add hexa values in C#? And i also want to know the max length of Hexa values and which Instance hold these values.
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6 Answers
C# supports hexadecimal literals:
int i = 0xff;
However, they have the same numeric values as decimal literals - you are limited by the type you use. There isn't a special Hexa type.
If you have an integer and want to display is in hexadecimal base, you can use the x format (example):
int i = 255;
Console.Write(i.ToString("x")); // ff
Console.Write(i); // 255
Note that writing i = 0xff or i = 255 is exactly the same - the value is resolved by the compiler, and you get the same compiled code.
Lastly, if you have strings with hexadecimal numbers, you can convert them to integers, sum them, and reformat them (example):
string hexValue = "af";
int i = Convert.ToInt32(hexValue, 16); //175
2 Comments
Hset Hset Aung
Yes, thanks for your answer. But my Hexa value contains 64 characters so which instance can hold this when convert to some type?
Kobi
@Hset Hset Aung - You should have mentioned you have such huge values
:). I've added another answer.For 64 character numbers, you need to use the BigInteger type of .Net 4, the normal types are too small:
BigInteger bi1 = BigInteger.Parse("123456789012345678901234567890123456789012345678901234567890abc5", NumberStyles.HexNumber);
BigInteger bi2 = BigInteger.Parse("123456789012345678901234567890123456789012345678901234567890abc1", NumberStyles.HexNumber);
BigInteger sum = BigInteger.Add(bi1, bi2);
Console.WriteLine("{0:x}", sum); //or sum.ToString("x")
(remember adding a reference to System.Numerics)
3 Comments
Hset Hset Aung
But , i use .Net 3.5 version. I am sorry to ask again, how can i solve in .Net version 3.5
Kobi
@Hset Hset Aung - In that case you need a library. Here are a few options: stackoverflow.com/questions/176775/big-integers-in-c
Hset Hset Aung
Thanks a lot for your answers.Ok , i check at that link now.
int a = 0x2;
int b = 0x5f;
int value = a + b; //adding hex values
string maxHex = int.MaxValue.ToString("x"); //maximum range of hex value as int
Comments
You can use this code for sum your result. You can see more on my ByteConverters class
public static long HexLiteralToLong(string hex)
{
if (string.IsNullOrEmpty(hex)) throw new ArgumentException("hex");
int i = hex.Length > 1 && hex[0] == '0' && (hex[1] == 'x' || hex[1] == 'X') ? 2 : 0;
long value = 0;
while (i < hex.Length)
{
int x = hex[i++];
if
(x >= '0' && x <= '9') x = x - '0';
else if
(x >= 'A' && x <= 'F') x = (x - 'A') + 10;
else if
(x >= 'a' && x <= 'f') x = (x - 'a') + 10;
else
throw new ArgumentOutOfRangeException("hex");
value = 16 * value + x;
}
return value;
}
Usage :
var HexSum = HexLiteralToLong("FF") + HexLiteralToLong("FF");
Result :
510
Comments
Hexadecimal values are just plain old integers (after all, the number 10 in base ten and the number A in hexadecimal are the same thing, just viewed differently); if you need to convert one to a hex string, use: value.ToString("X"), where value is an integral type (like int).
Comments
On your last question: you can use hexadecimal constants in integer types (byte, short, int and long). In C# long is 64 bit, so longest hexadecimal constant is 0x1234567812345678 (or any other with 16 hexadecimal digits).
2 Comments
Kobi
Well, not really any value with 16 digits, they aren't all equal, and half of them are too big - the maximal value for long is
0x7fffffffffffffff: ideone.com/tdpIX , which is also visible in the specifications: msdn.microsoft.com/en-us/library/system.int64.maxvalue.aspxKobi
Oh, I get it. You're talking about maximal length, not value.