change a drawable color programmatically in android

Question

i have the following parallelogram shape :

<vector xmlns:android="http://schemas.android.com/apk/res/android"
    android:width="200dp"
    android:height="50dp"
    android:viewportWidth="200"
    android:viewportHeight="50">

    <path android:fillColor="#000000"
    android:pathData="M 200 0 L 20 0 L 0 50 L 180 50 L 200 0" />
</vector>

and i have used it in this way

    <View

        android:layout_width="66dp"
        android:layout_height="26dp"
        android:layout_centerInParent="true"
        android:layout_marginEnd="8dp"
        android:layout_marginLeft="8dp"
        android:layout_marginRight="8dp"
        android:layout_marginStart="8dp"
        android:layout_marginTop="112dp"
        android:background="@drawable/shape"
        android:onClick="test"
        android:tag="p112"
        app:layout_constraintHorizontal_bias="0.615"
        app:layout_constraintLeft_toLeftOf="parent"
        app:layout_constraintRight_toRightOf="parent"
        app:layout_constraintTop_toTopOf="parent" />

now i want to change its color from black to white after tapping. function "test" would trigger after touching. but all i have found changes the color of background that would make my black parallelogram to a white rectangle. is there any way i can change its color. even manipulating the xml would be fine. tnx

test function:

    public void test(View view){
        view.setBackgroundColor(Color.WHITE);
    }

You need a new drawable that's white, by the way, if you are wanting to only change the shape color — OneCricketeer
– OneCricketeer, Commented May 22, 2017 at 13:09
@cricket_007 you mean i create a new one and exactly place it on the touched shape? is there any way i set the color to each view separately? — user5210131
– user5210131, Commented May 22, 2017 at 13:19

Barış Söbe · Accepted Answer · 2017-05-22 18:26:02Z

9

Drawable backgroundDrawable = DrawableCompat.wrap(view.getBackgroundDrawable()).mutate(); DrawableCompat.setTint(backgroundDrawable, color); You can use this!!

answered May 22, 2017 at 18:26

Barış Söbe

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2 Comments

user5210131 Over a year ago

instead of getBackgroundDrawable() I used getBackground() and it worked. thanks a million

user5210131 Over a year ago

but i have another problem...i made my parallelogram transparent with border, calling test function just changers the border color but when i set a color (not transparent) for my shape, test function would change its fill color. what shall i do?

Dishonered · Accepted Answer · 2017-05-22 13:10:40Z

1

You cannot change the color of individual path at runtime. You can however , change the color of entire vector.

answered May 22, 2017 at 13:10

Dishonered

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1 Comment

user5210131 Over a year ago

i have 64 of this shape and want to change the only one which is touched not all of them. is it possible? cause i think changing the whole vector color would change all my 64 shapes.

user6547359 · Accepted Answer · 2017-05-22 13:18:58Z

0

Try using setBackgroundTint instead of color. that should alter the resource of the background.

answered May 22, 2017 at 13:18

user6547359

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