Find unique elements from first array not repeated in second array using js [duplicate]

Question

I have two arrays

array1 = ["ab", "xyz", "qr", "pqrs"]
array2 = ["ab", "def", "lmno", "def", "qr", "pqrs"]

how to compare these two arrays and get a third array of the element from first array which is not found in second array.

Desired result:

unique = ["xyz"]

Thanks in advance

@str the question u posted is using jquery and i needed a solution with javascript. — zachi
– zachi, Commented Apr 25, 2017 at 10:55

kind user · Accepted Answer · 2017-04-25 10:47:29Z

2

Possible solution using Array#filter.

var array1 = ["ab", "xyz", "qr", "pqrs"],
    array2 = ["ab", "def", "lmno", "def", "qr", "pqrs"],
    unique = array1.filter(v => array2.indexOf(v) == -1);
    
    console.log(unique);

answered Apr 25, 2017 at 10:47

kind user

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Comments

tanmay · Accepted Answer · 2017-04-25 10:48:19Z

1

You can use Array.filter.

Here in this snippet, it checks whether every element of array1 is part of array2 using filter and includes

var array1 = ["ab", "xyz", "qr", "pqrs"]
var array2 = ["ab", "def", "lmno", "def", "qr", "pqrs"]

var unique = array1.filter(cur => !array2.includes(cur))
console.log(unique)

answered Apr 25, 2017 at 10:48

tanmay

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1 Comment

tanmay Over a year ago

@downvoter, what's wrong with this answer?

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