I am looking for an answer in internet but it no one that fit my needs.
I have a string in the following format:
"[2,15,23]"
and i am trying to convert it in this format:
[2,15,23]
I need the type after the convertion to change to []int. I need to convert it because i want to use it later to make an interface type to use it in a sql query as param.
Is there any way to convert it?
Thanks
A better way using json.Unmarshal:
func main() {
str := "[2,15,23]"
var ints []int
err := json.Unmarshal([]byte(str), &ints)
if err != nil {
log.Fatal(err)
}
fmt.Printf("%v", ints)
}
This is slightly hackish but you could treat it like a csv:
import (
"encoding/csv"
"strings"
)
in := `"[2,15,23]"`
r := csv.NewReader(strings.NewReader(in))
records, err := r.ReadAll()
Here is a working example if you haven't figured it out based on the comments suggesting that you use json.Unmarshal
package main
import (
"fmt"
"log"
"encoding/json"
)
func main() {
str := "[2,15,23]"
ints, err := convertToIntSlice(str)
if err != nil {
log.Fatal(err)
}
fmt.Printf("%v", ints)
}
type IntSlice struct {
Ints []int
}
func convertToIntSlice(s string) ([]int, error) {
a := &IntSlice{}
err := json.Unmarshal([]byte(`{"Ints":`+s+"}"), a)
return a.Ints, err
}
