Replace characters in string in swift?

Question

I have a string as "12:66 PM".Now i want to replace string 66 with 60.So i want to check if that after ":" two characters should be replaced with 60 or any value.

please suggest

Are you just replacing characters after :, or are you trying to change a date / time value? If it's the latter, there are better ways to handle this — Ashley Mills
– Ashley Mills, Commented Jan 11, 2017 at 12:31
This is a basic string processing question. SO is not a place to get others to write your code for you. Make an attempt at your own solution to the problem and we'll help you get it working. — Duncan C
– Duncan C, Commented Jan 11, 2017 at 14:12
Or, as Ashley rightly points out, it might be a date and time processing problem. You should probably step back and describe what you're trying to do in more general terms, and your current approach. If you're trying to manipulate dates and times there are indeed better ways to do it. — Duncan C
– Duncan C, Commented Jan 11, 2017 at 14:14

Raphael · Accepted Answer · 2017-01-11 16:36:51Z

You can use regexp-search-and-replace:

string.replacingOccurrences(of: "regexp", with: "replacement", options: .regularExpression)

So, in your case:

var time = "12:66 PM"
time.replacingOccurrences(of: ":\\d\\d", with: ":60", options: .regularExpression)
// > "12:60 PM"

Abstracting this into a function is straight-forward:

func replaceMinutes(in time: String, with minutes: String) -> String {
    return time.replacingOccurrences(of: ":\\d\\d", 
                                     with: ":\(minutes)", 
                                     options: .regularExpression)
}

If necessary, you may want to check that the input strings match what you expect:

    nil != time.range(of: "^\\d\\d:\\d\\d [AP]M$", options: .regularExpression)
&&  nil != minutes.range(of: "^\\d\\d$", options: .regularExpression)

If you have trouble understanding how any of this works, I recommend you read up on a) basics of the Swift language and b) regular expressions.

Nitin Thakor · Accepted Answer · 2017-01-11 12:38:26Z

-5

Here Is the Logic how can you do that first of all you have o take last index of your input var

in Java we can do like this

String l_name = input .substring(input .lastIndexOf(":"));

And after That you can replace l_name with your new output with variable i hope it will help..

answered Jan 11, 2017 at 12:38

Nitin Thakor

679 bronze badges

Collectives™ on Stack Overflow

Replace characters in string in swift?

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related