Terminal not reading a for-loop statement [duplicate]

Question

I have failed many times when executing a code, I thought it was in my logic in how I use loop statements, but when I tried this code:

int main(){
    cout << "yo \n";
    for(int i; i < 5; i++){
        cout << "meh \n";
    }
}

I was expecting the output:

    yo
    meh
    meh
    meh
    meh
    meh

But in my disappointment, it only showed

yo

So, what's the problem with this simple block of code?

msc · Accepted Answer · 2016-12-17 07:15:56Z

3

Because i is uninitialized. Initialize the i value, Like

for(int i = 0; i < 5; i++)

uninitialized variables to hold garbage data.So, this is undefined behaviour.

answered Dec 17, 2016 at 6:58

msc

35.1k32 gold badges129 silver badges221 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Saurav Sahu · Accepted Answer · 2016-12-17 07:08:43Z

1

It is failing many times because it is undefined behaviour to use uninitialized variable i. Any thing can happen in that case.

answered Dec 17, 2016 at 7:08

Saurav Sahu

14.1k9 gold badges73 silver badges85 bronze badges

Ruben Bhattacharya · Accepted Answer · 2016-12-17 07:40:43Z

0

Initialise the value of i.i++ is trying to increment an uninitialised variable.

answered Dec 17, 2016 at 7:40

1325 bronze badges