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I saw there are several topics on removing items from a list, including using remove(), pop(), and del. But none of these is what I am looking for, since I want to get a new list when the items are removed. For example, I want to do this:

a = [1, 2, 3, 4, 5, 6]
<fill in >       # This step somehow removes the third item and get a new list b and let
b = [1, 2, 4, 5, 6]

How can I do this?

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  • So what exactly is wrong with a.pop(2)? Commented Nov 21, 2016 at 10:01
  • 2
    @barakmanos i believe it returns element and not new list object as OP want it. Commented Nov 21, 2016 at 10:05
  • @khelwood OP wants to create new list without the 3rd item, not without the int 3 Commented Nov 21, 2016 at 10:07
  • 2
    b = a[:2]+a[3:] Commented Nov 21, 2016 at 10:08
  • 1
    b=a[:];b.pop(2) ??? Commented Nov 21, 2016 at 10:15

1 Answer 1

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46

If you want to have a new list without the third element then:

b = a[:2] + a[3:]

If you want a list without value '3':

b = [n for n in a if n != 3]
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1 Comment

b = a[:2] + a[3:] it is. Thanks @Yevhen. I thought Python has something built-in function to do this, well, maybe not. But this is an excellent solution!

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