swagger: file path in path parameter

Question

Here is my api requirement

GET http://localhost:8080/filePath/{path}

For example:

curl http://localhost:8080/filePath/home/users/user/one.txt

Here is yaml config:

parameters:
        - name: path
          in: path
          description: Todo description
          type: string
          required: true

But I'm getting 404 error. How can I use file path in path parameter?

Possible duplicate of Swagger: wildcard path parameters

Helen
– Helen

2019-05-22 20:30:01 +00:00
Commented May 22, 2019 at 20:30 — Helen
– Helen, Commented May 22, 2019 at 20:30

Helen · Accepted Answer · 2022-01-26 10:44:05Z

3

OpenAPI 2.0 (Swagger 2.0), 3.0, and 3.1 do not allow you to use slashes in path parameters, so you can't do that. There's an open feature request for this:

https://github.com/OAI/OpenAPI-Specification/issues/892

edited Jan 26, 2022 at 10:44

Helen

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answered Nov 3, 2016 at 10:36

Ron

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