Exception handling code doubt

Question

I am very new to this topic. Please bare with my silly doubts. I have the following code where I get a name from user and if its null sone exception is thrown. But here i m not getting any exception it i enter null. Please help me

import java.io.*;
class dbz
{
    public static void main(String args[])
    {
        String s=null;
        try
        {

           BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
           s=br.readLine();
        }
        catch(IOException e)
        {
           System.out.println(e.getMessage());
        }
        System.out.println(s);
    }
}

Could you clarify what is happening, and what you expect to happen? It's not entirely clear to me what the problem is. — Andrzej Doyle
– Andrzej Doyle, Commented Oct 27, 2010 at 7:48
please include some more information regarding expected vs. actual behavior. — jjnguy
– jjnguy, Commented Oct 27, 2010 at 13:27

Ignacio Vazquez-Abrams · Accepted Answer · 2010-10-27 06:46:59Z

2

You will never receive null as user input from the console, and it would not trigger a IOException regardless.

answered Oct 27, 2010 at 6:46

Ignacio Vazquez-Abrams

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Comments

asela38 · Accepted Answer · 2010-10-27 07:44:19Z

0

modify your code as below then you'll see the problem for yourself

import java.io.*; 
class dbz 
{ 
  public static void main(String args[])  throws IOException
  { 
       BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); 
       System.out.println(br.readLine()); 
   } 
}

answered Oct 27, 2010 at 7:44

asela38

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