User Defined and built in Arguments in exceptions

Question

The following code when executed doesn't result in argument( i.e : Divide by Zero is not permitted ) being printed. It only gives built in error message from- ZeroDivisionError. So, whats the use of user defined arguments when built in error messages are available.

print "Enter the dividend"
dividend=input()
print "Enter the divisor"
divisor=input()

try:
    result=dividend/divisor
except "ZeroDivisonError",argument:
    print "Divide by Zero is not permitted \n ",argument # Argument not getting printed
else:   
    print "Result=%f" %(result)

@Rogalski: It's valid, just absolutely not what you want to do. — Ignacio Vazquez-Abrams
– Ignacio Vazquez-Abrams, Commented Jul 15, 2016 at 15:10

RandomEli · Accepted Answer · 2016-07-15 15:23:22Z

0

Make your Exception generic works:

dividend=int(input("Enter the dividend: "))
divisor=int(input("Enter the divisor: "))

try:
    result=dividend/divisor
except Exception,argument:
    print "Divide by Zero is not permitted \n ",str(argument) # Argument not getting printed
else:   
    print "Result=%f" %(result)

And if your want to define your own exception, follow this way:

# Define a class inherit from an exception type
class CustomError(Exception):
    def __init__(self, arg):
        # Set some exception infomation
        self.msg = arg

try:
    # Raise an exception with argument
    raise CustomError('This is a CustomError')
except CustomError, arg:
    # Catch the custom exception
    print 'Error: ', arg.msg

You can find this template here: Proper way to define python exceptions

edited Jul 15, 2016 at 15:23

answered Jul 15, 2016 at 15:16

RandomEli

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7 Comments

Butters Over a year ago

It works now. The spelling of division in ZeroDivisonError is wrong!. But after fixing it, argument is getting printed now.

RandomEli Over a year ago

There's nothing wrong with ZeroDivisionError, but what he wrote in line is a string. This should be an object from the Exception class, not a string.

frist Over a year ago

@LingboTang print accepts objects also and print them successfully

RandomEli Over a year ago

@frist Again, it isn't a problem with print(). However, the syntax he used to throw the exception is not correct.

RandomEli Over a year ago

@Butters If you want to accept this answer, you can click the check sign.

|

Butters · Accepted Answer · 2016-09-09 15:52:58Z

0

The spelling of "ZeroDivisonError" is incorrect and moreover it shouldnt be in "". Correct line:

    except ZeroDivisionError,argument:
    print "Divide by Zero is not permitted \n ",argument

edited Sep 9, 2016 at 15:52

answered Jul 15, 2016 at 15:26

Butters

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