Calling Objective-C method with blocks from Swift

Question

I have a method in Objective-C as follows:

- (void)myFunction:(void (^)(NSArray *data))successBlock error:(void (^)(NSError *error))errorBlock {
    //...//
    successBlock(someData);
}

I want to call it from Swift, but I can't understand the syntax.

Whatever I try it complains:

SomeClass.sharedInstance().myFunction(
    successBlock: {
        (data) in
        print(data)
    },
    error: {
        (error) in
        print(error)
    })

Cannot call value of non-function type

'(((([AnyObject]!) -> Void!, error: ((NSError!) -> Void)!) -> Void)!

The code completion is supposed to suggest you the proper syntax — vadian
– vadian, Commented May 24, 2016 at 12:58
If I autocomplete the suggestion Xcode gives me it fails with the same error — John Anthony
– John Anthony, Commented May 24, 2016 at 13:00

vadian · Accepted Answer · 2016-05-24 13:10:18Z

1

This Swift equivalent is

SomeClass.sharedInstance().myFunction({ data in
     print(data) 
   }) { error in 
     print(error) 
   }

If you need the parameter names successBlockand errorBlock you have to declare them on the ObjC side.

answered May 24, 2016 at 13:10

vadian

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