Convert list into tuple then add this tuple into list in python

Question

Hi I want my output to be

add_sizes(['hello', 'world']) -> [('hello', 5), ('world', 5)]

but I'm getting

add_sizes(['hello', 'world']) -> [('hello', 5), ('hello', 5, 'helloworld', 5)]

My code is

def add_sizes(strings):

    s = ()
    t=[]
    m=[]
    for i in strings:
        x=i
        for i,c in enumerate(list(x)):
            t.append(c)
        l=(str(''.join(t)),i+1)
        s += l
        m.append(s)
    print(m)

Any suggestion would be appreciated thanks

I think you're over-complicating it a bit. You just need tuples containing every string in strings along with the len() of the string. Append these, one by one, to a list and return/print the list when you're done. Your enumerate and l=(str(''.join(t)),i+1) statements aren't necessary — jDo
– jDo, Commented Apr 7, 2016 at 23:46
The cause of your issue is where you have s=();t=[] (should be inside the loop) but as eugene y says, the better solution is a list comprehension. — zehnpaard
– zehnpaard, Commented Apr 7, 2016 at 23:47

Eugene Yarmash · Accepted Answer · 2016-04-07 23:50:57Z

8

Just use a list comprehension:

>>> def add_sizes(strings):
...     return [(s, len(s)) for s in strings]
... 
>>> 
>>> add_sizes(['hello', 'world'])
[('hello', 5), ('world', 5)]

Or if you want to do it in-place:

>>> def add_size(strings):
...     for i, s in enumerate(strings):
...         strings[i] = (s, len(s))
...     return strings
... 
>>> add_sizes(['hello', 'world'])
[('hello', 5), ('world', 5)]

edited Apr 7, 2016 at 23:50

answered Apr 7, 2016 at 23:46

Eugene Yarmash

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1 Comment

Reboot Over a year ago

thanks it works like a charm, I didn't know that we can do it this way. much appreciated!

jDo · Accepted Answer · 2016-04-07 23:55:58Z

1

Someone already gave a complete solution so I'll just post mine too:

def add_sizes(strings):
    l = []
    for string in strings:
        l.append((string, len(string)))
    return l

def add_sizes(strings):
    return [(s, len(s)) for s in strings]

edited Apr 7, 2016 at 23:55

answered Apr 7, 2016 at 23:49

jDo

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