Call a function and print function's name

Question

I have a very long list of functions and I am hoping to be able to call them and have them print their name and when they are completed as show below.

def call(*functions):
    for f in functions:
        print(f.__name__)
        f()
        print('{} completed'.format(f.__name__))

call(lambda: (long(), lst(), of(), func(), ions()...))

I do not want to have to write print(f.__name__) ... print('{} completed'.format(f.__name__)) around every function. However, in the code above it prints 'lambda' (as expected). how can I automate these function calls/print statements so it prints correctly?

DevLounge · Accepted Answer · 2016-04-08 05:24:59Z

1

def call(*functions):
    for f in functions:
        print(f.__name__)
        f()
        print('{} completed'.format(f.__name__))

call(long, lst, of, func, ions...)

However, it would be more logical to use map and simplify call:

def call(function):
    print(f.__name__)
    f()
    print('{} completed'.format(f.__name__))

map(call, (long, lst, of, func, ions...))

edited Apr 8, 2016 at 5:24

answered Apr 7, 2016 at 22:57

DevLounge

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3 Comments

af3ld Over a year ago

is there a way to do this where each function has different arguments? I'm playing with functools.partial, but 'functools.partial' object has no attribute __name__

DevLounge Over a year ago

Yes but it becomes metaprogramming using a decorator like pattern and so on.... (Sorry I'm on my phone and can't help on it more right now but ill have a look at it...)

af3ld Over a year ago

@Apero no worries, I figured it out. Instead of f.__name__ which creates a partial object, you need to call f.func.__name__ which prints the function's name

DaveBensonPhillips · Accepted Answer · 2016-04-07 23:03:56Z

1

You nearly have the right idea, but you want to pass the functions themselves to call rather than a lambda.

As your code currently stands, you are only passing one function, the lambda, which calls the other functions between your print statements.

Change

call(lambda: (long(), lst(), of(), func(), ions()...))

to

call(long, lst, of, func, ions...))

edited Apr 7, 2016 at 23:03

answered Apr 7, 2016 at 22:56

DaveBensonPhillips

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