Integer to Alphanumeric string conversion

Question

I need to convert five digit integer to alphanumeric string of length 5.Doing below but sometimes it doesn't provide alphanumeric but numeric value.

Long x = 12345L;
String code = Long.toHexString(x).toUpperCase();

I want to get Alphanumeric string of length 5 always.

What do you mean by "alphanumeric value"? You want to convert it to String? — Maroun
– Maroun, Commented Feb 22, 2016 at 8:35
As such there are no rules,from client side i will generate some TOTP of five digit and then convert it to alphanumeric string of same length and then this data will travel through to backend,and on back end side similar TOTP logic will run and will again generate alphanumeric string. I am doing this just to encode this numeric value,i have space constraint because of vendor,only 5 character are permitted. — dReAmEr
– dReAmEr, Commented Feb 22, 2016 at 8:41

user4910279 · Accepted Answer · 2016-02-22 09:16:00Z

2

Try this

static String alphaNumric(int value) {
    String s = "abcde" + Integer.toString(value, 36);
    return s.substring(s.length() - 5);
}

and

    int[] tests = { 12345, 1, 36, 36 * 36, 32767, 99999 };
    for (int i : tests)
        System.out.println(i + " -> " + alphaNumric(i));

output

12345 -> de9ix
1 -> bcde1
36 -> cde10
1296 -> de100
32767 -> depa7
99999 -> e255r

answered Feb 22, 2016 at 9:16

user4910279

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Comments

Bathsheba · Accepted Answer · 2016-02-22 09:37:23Z

0

That's hardly surprising.

For example, 0x12345 is 74565, so 74565 does not contain any of the digits A to F when converted to hexadecimal.

Given that 99999 is 0x1869F, you have plenty of room in your converted string to accommodate some "junk" data, consider introducing an additive constant (0xA0000 perhaps which at least guarantees at least one alpha character for positive inputs), or even a number that your XOR with your original.

edited Feb 22, 2016 at 9:37

answered Feb 22, 2016 at 8:40

Bathsheba

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