string split in bash

Question

In a Bash script I would like to split a line into pieces and put them into an array.

The line:

ParisABFranceABEurope

I would like to split them in an array like this (with AB):

array[0] = Paris
array[1] = France
array[2] = Europe

I would like to use simple code, the command's speed doesn't matter. How can I do it?

Possible duplicate of How do I split a string on a delimiter in Bash? — Cripto
– Cripto, Commented Feb 18, 2016 at 2:25

Gene · Accepted Answer · 2016-02-19 00:33:40Z

4

Here is one that doesn't need sub-shells (i.e. it's all built-in). You'll need to pick a single delimiter character (here @) that can't appear in the data:

str='ParisABFranceABEurope'
IFS='@' read -r -a words <<< "${str//AB/@}"

echo "${words[0]}"
echo "${words[1]}"
echo "${words[2]}"

Drum roll, please...

$ source foo.sh
Paris
France
Europe

edited Feb 19, 2016 at 0:33

answered Feb 18, 2016 at 2:57

Gene

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1 Comment

mklement0 Over a year ago

Nicely done; to encourage good habits, please double-quote ${words[0]}, ..., and use -r with read.

riteshtch · Accepted Answer · 2016-02-18 02:45:52Z

0

$declare -a array=($(echo "ParisABFranceABEurope" | awk -F 'AB' '{for (i=1;i<=NF;i++) print $i}'))
$ echo "${array[@]}"
Paris France Europe

answered Feb 18, 2016 at 2:45

riteshtch

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1 Comment

mklement0 Over a year ago

This works for the sample input, but the caveat is that it makes the resulting tokens subject to pathname expansion.

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