Python: sorting a list by "column" [duplicate]

Question

How can I sort a list-of-lists by "column", i.e. ordering the lists by the ith element of each list?

For example:

a=[['abc',5],
   ['xyz',2]]

print sortByColumn(a,0)

[['abc',5],
 ['xyz',2]]

print sortByColumn(a,1)

[['xyz',2],
 ['abc',5]]

There is a similar question here [How to sort (list/tuple) of lists/tuples?][1] [1]: stackoverflow.com/questions/3121979/… — Hooting
– Hooting, Commented Aug 21, 2015 at 5:16

Community · Accepted Answer · 2017-05-23 11:44:01Z

9

You could use sort with its key argument equal to a lambda function:

sorted(a, key=lambda x: x[0])
[['abc', 5], ['xyz', 2]]

sorted(a, key=lambda x: x[1])
[['xyz', 2], ['abc', 5]]

Another way would be to use key with operator.itemgetter, which creates the required lambda function:

from operator import itemgetter
sorted(a, key=itemgetter(1))
[['xyz', 2], ['abc', 5]]

CommunityBot

11 silver badge

answered Aug 21, 2015 at 5:15

The6thSense

8,3459 gold badges38 silver badges67 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1