processing JSON file using jq in bash

Question

I have the following bash script

counter=0
for file in /home/ec2-user/Workspace/events_parts/*
do
        counter=$[counter + 1]
        event=$(cat $file | jq '.Event')
        echo $event
        if [ "$event" = "Page Exceeded" ]  || [ "$event" = "Reporting Time" ]; then
                echo "Coming Here"
                jq ".url = \"$(jq '.Message' $file | sed 's/.*proxy=\([^&]*\).*/\1/')\"" $file  > events_parts/out_$file
        else
                jq ".url = null" $file > events_parts/out_$file
        fi
done

It does processing of a set of JSON files.I want to redirect it to a filename which has out_$input_file_name. But the variable file prints out the whole path not just the file name (for e.g. /home/ec2-user/Workspace/events_parts/input.json) How do I get just the "input file name" from this?

possible duplicate of processing a JSON file usign jq in bash — ShellFish
– ShellFish, Commented Mar 18, 2015 at 1:40

Cyrus · Accepted Answer · 2015-03-18 00:52:21Z

1

Try this:

file="/home/ec2-user/Workspace/events_parts/input.json"
filename="$(basename "$file")"
echo "$filename"

Output:

input.json

answered Mar 18, 2015 at 0:52

Cyrus

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