regular expression to get the domain name in javascript?

Question

I am having a problem with regular expression for getting the main domain name from a url. that is if i am having urls as given below..

http://domain.com/return/java.php?hello.asp
http://www.domain.com/return/java.php?hello.asp
http://blog.domain.net/return/java.php?hello.asp
http://us.blog.domain.co.us/return/java.php?hello.asp
http://domain.co.uk
http://domain.net
http://www.blog.domain.co.ca/return/java.php?hello.asp
http://us.domain.com/return/

from all this I should only get domain as the output of the regular expression.. so how do i do it? i used;

var url = urls.match(/[^.]*.(com|net|org|info|coop|int|co\.uk|org\.uk|ac\.uk|uk)/g);

but it does not work for

  http://domain.net

so can someone help me out with this.

Domain may end by "/" or end-of-line, so "match(/[^.]*.(com|net|org|info|coop|int|co\.uk|org\.uk|ac\.uk|uk)(/|$)g)" may work. — Fumu 7
– Fumu 7, Commented Jan 6, 2015 at 8:09
Seems to be working, regex101.com/r/dL6nN7/2 and jsbin.com/zanivonijo/1/edit?js,console but I might be missing the point? — Henrik Andersson
– Henrik Andersson, Commented Jan 6, 2015 at 8:10
don't forget the escape signs for the . since it is a special character, after the [^.]* part. :) — winner_joiner
– winner_joiner, Commented Jan 6, 2015 at 8:41
@SusanWilliams did you find a solution, or do you still need some help. :) — winner_joiner
– winner_joiner, Commented Jan 8, 2015 at 6:55

nu11p01n73R · Accepted Answer · 2015-01-06 08:24:16Z

4

You can use URL rather than regex

var url  = new URL("http://domain.com/return/java.php?hello.asp");
console.log(url.hostname);
=> domain.com

OR

If you want the protocol as well

var url  = new URL("http://domain.com/return/java.php?hello.asp");
console.log(url.protocol+"//"+url.hostname);
= > http://domain.com

answered Jan 6, 2015 at 8:24

nu11p01n73R

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1 Comment

Salman Arshad Over a year ago

IE support is an issue.

Tuncay Göncüoğlu · Accepted Answer · 2015-01-06 08:51:41Z

0

would this help ?

(http|https|ftp):\/\/([a-zA-Z0-9.])+/g

matches at

http://domain.com
http://www.domain.com
http://blog.domain.net
http://us.blog.domain.co.us
http://domain.co.uk
http://domain.net
http://www.blog.domain.co.ca
http://us.domain.com

answered Jan 6, 2015 at 8:51

Tuncay Göncüoğlu

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Comments

winner_joiner · Accepted Answer · 2015-01-06 09:07:00Z

Here is a solution changing the regex a bit:

url.match(/https?:\/\/[^/]+((?=\/)|$)/g);
//tested with Chrome 38+ on Win7

Basiclly checking for slash / or string end $

Update replaced jsFiddle link with inline Stackoverflow-Code:

var urls = ['http://domain.com/return/java.php?hello.asp',
  'http://www.domain.com/return/java.php?hello.asp',
  'http://blog.domain.net/return/java.php?hello.asp',
  'http://us.blog.domain.co.us/return/java.php?hello.asp',
  'http://domain.co.uk',
  'http://domain.net',
  'http://www.blog.domain.co.ca/return/java.php?hello.asp',
  'http://us.domain.com/return/'
];

var htmlConsole = document.getElementById("result");
var htmlTab = "&nbsp;&nbsp;&nbsp;&nbsp;";
var htmlNewLine = "<br />";

htmlConsole.innerHTML = "";
for (var id in urls) {

  htmlConsole.innerHTML += "URL: " + urls[id] + htmlNewLine;

  var matchResults = urls[id].match(/https?:\/\/[^/]+((?=\/)|$)/g);

  for (var innerIdx in matchResults) {
    htmlConsole.innerHTML += htmlTab + "MatchNumber: " + innerIdx + " MatchValue: " + matchResults[innerIdx] + htmlNewLine;
  }

  htmlConsole.innerHTML += htmlNewLine;

}

<div id="result">
</div>

bw_üezi · Accepted Answer · 2015-01-06 08:37:10Z

-1

var url = urls.match(/[^./]*.(com|net|org|info|coop|int|co\.uk|co\.us|co\.ca|org\.uk|ac\.uk|uk)/g);

just added a / and updated the list of top-level domains to match your examples.
Although I do not recommend to keep the list of top-level domains within a regexp. it's just too many. http://en.wikipedia.org/wiki/List_of_Internet_top-level_domains

edited Jan 6, 2015 at 8:37

answered Jan 6, 2015 at 8:25

bw_üezi

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