I need to sort string, and I came up with the following function.
def mysort(comb_):
str = []
size = len(comb_)
for c in comb_:
str.append(c)
str.sort()
return ''.join(str)
Is there any way to make it compact?
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4 Answers
return ''.join(sorted(comb_))
answered Apr 8, 2010 at 2:13
Ignacio Vazquez-Abrams
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1 Comment
jemfinch
This is the correct answer. It cannot get more succinct (or idiomatic) than that. Disregarding the strange underscore in the variable name, of course.
def sortstr(comb_):
return ''.join(sorted(comb_))
e:f;b :(
Comments
If you want to get a string back do this:
def sort_string(string):
return "".join(sorted(string))
But if you want a list back, do this:
def sort_string(string):
return sorted(string)
Comments
def sort_string(s):
def sort_string_to_a_list(s):
return sorted(s, lambda x,y: cmp(x.lower(), y.lower()) or cmp(x,y))
sorted_list = sort_string_to_a_list(s)
return ''.join(sorted_list)
