PHP & MySQL: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given [duplicate]

Question

I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem?

I get the following error.

on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

line 22 is.

if (mysqli_num_rows($dbc) == 0) {

Here is the php code.

if (isset($_POST['submitted'])) { // Handle the form.

    require_once '../../htmlpurifier/library/HTMLPurifier.auto.php';

    $config = HTMLPurifier_Config::createDefault();
    $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding
    $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype
    $purifier = new HTMLPurifier($config);


    $mysqli = mysqli_connect("localhost", "root", "", "sitename");
    $dbc = mysqli_query($mysqli,"SELECT users.*, profile.*
                                 FROM users 
                                 INNER JOIN contact_info ON contact_info.user_id = users.user_id 
                                 WHERE users.user_id=3");

    $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me']));
    $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests']));



if (mysqli_num_rows($dbc) == 0) {
        $mysqli = mysqli_connect("localhost", "root", "", "sitename");
        $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) 
                                     VALUES ('$user_id', '$about_me', '$interests')");
}



if ($dbc == TRUE) {
        $dbc = mysqli_query($mysqli,"UPDATE profile 
                                     SET about_me = '$about_me', interests = '$interests' 
                                     WHERE user_id = '$user_id'");

        echo '<p class="changes-saved">Your changes have been saved!</p>';
}


if (!$dbc) {
        // There was an error...do something about it here...
        print mysqli_error($mysqli);
        return;
}

}

Sean Vieira · Accepted Answer · 2010-03-30 15:17:10Z

47

$dbc is returning false. Your query has an error in it:

SELECT users.*, profile.* --You do not join with profile anywhere.
                                 FROM users 
                                 INNER JOIN contact_info 
                                 ON contact_info.user_id = users.user_id 
                                 WHERE users.user_id=3");

The fix for this in general has been described by Raveren.

answered Mar 30, 2010 at 15:17

Sean Vieira

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1 Comment

Aimal Khan Over a year ago

The phrase "Your query has an error in it" did the job for me. Thanks!

raveren · Accepted Answer · 2010-03-30 15:15:00Z

45

The query either returned no rows or is erroneus, thus FALSE is returned. Change it to

if (!$dbc || mysqli_num_rows($dbc) == 0)

mysqli_num_rows:

Return Values

Returns TRUE on success or FALSE on failure. For SELECT, SHOW, DESCRIBE or EXPLAIN mysqli_query() will return a result object.

answered Mar 30, 2010 at 15:15

raveren

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1 Comment

Alvaro Montoro Over a year ago

If no rows are returned, the query will be successful (0 records will not make mysqli_query or mysqli_num_rows return false).

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