How can I know during runtime that my code threw a Warning?
example
try {
echo (25/0);
} catch (exception $exc) {
echo "exception catched";
}
throws a "Warning: Division by zero" error that i can not handle on my code.
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3 Answers
You're looking for the function set_error_handler(). Check out the sample code in the manual.
Make sure that you don't only suppress the error warnings, but instead silently redirect them to a log file or something similar. (This helps you track down bugs)
2 Comments
Levi Hackwith
In going off what @svens said, error suppression for turning off all errors is done with
error_reporting(0) See us.php.net/manual/en/…
svens
.. or by prepending an '@' to the command. Btw. the error handler will also be called when error_reporting is set to zero (with errno=0). The error handler is very handy and can be used to do things like final logging of time, parameters, memory usage, etc and notify the admin (for fatal errors). I don't wanted to recommend suppressing errors :).
You need to handle the exception yourself as follows.e.g
function inverse($x)
{
if(!$x)
{
throw new Exception('Division by zero.');
}
else
{
return 1/$x;
}
}
try
{
echo inverse(5);
echo inverse(0);
}
catch (Exception $e)
{
echo $e->getMessage();
}
1 Comment
user187291
the purpose of exceptions is not to "prevent" errors from happening, like you do, but to provide a way of handling them when they happen. Still, +1 for trying.
You need to install an error handler that converts old style php "errors" into exceptions. See an example here
