5

I want to use \ in a string, like

string str="abc\xyz";

But this is giving me error.

I have also tried

string str="abc\\xyz";

But still it isnt working. Can anyone help me out?

8
  • (I agree with all answers, but) what is the result of the second try (which should work) and what were you expecting ? Commented Mar 12, 2010 at 12:09
  • Effectively a duplicate - stackoverflow.com/questions/1057926/when-to-use-in-c Commented Mar 12, 2010 at 12:10
  • That will definitely work - post a snippet if you are still having issues - perhaps it is somewhere other than that particular line. Commented Mar 12, 2010 at 12:10
  • 3
    Shouldn't the second example just be string str = "abc\\xyz" - i.e. just two back slashes? Having three gives "unrecognised escape sequence" Commented Mar 12, 2010 at 12:11
  • 1
    @Timores - the second result shouldn't work; there are three backslashes which results in \\ and \xyz - since \xyz is not valid hex, the compiler will reject it. Commented Mar 12, 2010 at 12:13

8 Answers 8

18

You can either escape the character, like so:

string str="abc\\xyz";

or use a verbatim string literal like so:

string str=@"abc\xyz";

So your second example should work.

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2 Comments

FYI, the latter is called a verbatim string literal.
Got an upvote on a 9 year old answer. I love this place.
5

Well, the latter ("abc\\xyz") will certainly result in a backslash in the string - or you could use a verbatim string literal:

string str = @"abc\xyz";

Note that if you use the debugger to look at your strings, it will often (always?) "escape" them for you, so you'd see "abc\\xyz". This can cause a fair amount of confusion. Either look at the characters individually, or print the string to the console.

You haven't said in what way it "isn't working" - could you give more details? If it's just the debugger output, then the above may be all you're looking for - but otherwise you should tell us what you're seeing vs what you expected to see.

Have a look at my article about strings for more information about strings in general, escaping, the debugger etc.

6 Comments

Yes. While debugging i see abc\\xyz when i used @"abc\xyz".
And due to this i am unable to do anything further in my code.
@Brigadier: But that's the correct data. Why does the debugger showing you the right data but as a verbatim string literal make you "unable to do anything further in [your] code"? What's actually stopping you from continuing? What unexpected results are you getting apart from seeing the string in verbatim string literal format?
I am extracting the substring after \ from abc\xyz i.e.i want xyz. But by writing string str=@"abc\xyz" i am getting \xyz.
@Brigadier: Then your code to extract the substring is broken. I suspect you're missing a "+1".
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string str="abc\\xyz";

Normally, this should work. An alternative is:

string str = @"abc\xyz";

Comments

2
public class Program
{
    static void Main(string[] args)
    {
        string str = "abc\\xyz";
        Console.WriteLine(str);
    }
}

This works fine. It prints abc\xyz.

Comments

2

You can do it like this

string str = @"abc\xyz";

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2
string str = @"abc\xyz";

Comments

1

You can do this:

string str = @"abc\xyz";

That tells says that the slash is significant and not an escape character.

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1

You'll need to prefix the string with the '@' symbol to stop the compiler trying to treat it as an escape sequence. So string str = @"abc\xyz"; should work.

Comments

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