how can i make my console application window to behave like a command prompt window and execute my command line arguments?
2 Answers
This should get you started:
public class Program
{
public static void Main(string[] args)
{
var proc = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = "cmd.exe",
CreateNoWindow = true,
UseShellExecute = false,
RedirectStandardInput = true,
RedirectStandardOutput = true,
RedirectStandardError = true
}
};
proc.Start();
new Thread(() => ReadOutputThread(proc.StandardOutput)).Start();
new Thread(() => ReadOutputThread(proc.StandardError)).Start();
while (true)
{
Console.Write(">> ");
var line = Console.ReadLine();
proc.StandardInput.WriteLine(line);
}
}
private static void ReadOutputThread(StreamReader streamReader)
{
while (true)
{
var line = streamReader.ReadLine();
Console.WriteLine(line);
}
}
}
The basics are:
- open cmd.exe process and capture all three streams (in, out, err)
- pass input from outside in
- read output and transfer to your own output.
The "Redirect" options are important - otherwise you can't use the process' respective streams.
The code above is very basic, but you can improve on it.
Comments
I believe you are looking for this
var command = "dir";
System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd", "/c " + command);
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
string result = proc.StandardOutput.ReadToEnd();
Console.WriteLine(result);
c# console application command line argumentsis msdn.microsoft.com/en-us/library/aa288457(v=vs.71).aspx