How to capture the output of a multi-line Bash snippet into a variable?

Question

I found a bit of code here that can be used to convert bases in bash neatly. How do I use it and get the result into a bash variable?

I tried something like below, but it did not work.

NUM_IN_DEC=12321
BASE36=($(echo {0..9} {a..z}))
NAME=(
    for i in $(bc <<< "obase=36; $NUM_IN_DEC"); do
        echo -n ${BASE36[$(( 10#$i ))]};
    done && echo
)
echo converted value is $NAME

iruvar · Accepted Answer · 2014-04-11 14:59:29Z

3

Just use command substitution to set NAME

NUM_IN_DEC=12321
BASE36=($(echo {0..9} {a..z}))
NAME=$(
    for i in $(bc <<< "obase=36; $NUM_IN_DEC"); do
        echo -n ${BASE36[$(( 10#$i ))]};
    done && echo
)
echo converted value is $NAME
9i9

answered Apr 11, 2014 at 14:59

iruvar

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