I am trying to save a text file in sqlite using python but when I try to retrieve the file, I see newline character and other characters. Is there any way to output the file as it is like the original file? Is there any work around.
import sqlite3
conn=sqlite3.connect('example.db')
c=conn.cursor()
c.execute("create table code_tag1 (language text, code BLOB, tag text)")
#c.execute("select * from sqlite_master")
with open("bubblesort_java.txt","rb") as f:
ablob=f.read()
c.execute("insert into code_tag1 values('java',?,'bubblesort')",[buffer(ablob)])
conn.commit()
row=c.execute("select * from code_tag1").fetchone()
print (repr(str(row[1])))
conn.close()
The output is :
'import java.util.Scanner;\r\n \r\nclass BubbleSort {\r\n public static void main(String []args)
{\r\n int n, c, d, swap;\r\n Scanner in = new Scanner(System.in);\r\n \r\n
System.out.println("Input number of integers to sort");\r\n n = in.nextInt();\r\n \r\n int
array[] = new int[n];\r\n \r\n System.out.println("Enter " + n + " integers");\r\n \r\n for
(c = 0; c < n; c++) \r\n array[c] = in.nextInt();\r\n \r\n for (c = 0; c < ( n - 1 );
c++) {\r\n for (d = 0; d < n - c - 1; d++) {\r\n if (array[d] > array[d+1]) /* For
descending order use < */\r\n {\r\n swap = array[d];\r\n array[d]
= array[d+1];\r\n array[d+1] = swap;\r\n }\r\n }\r\n }\r\n \r\n
System.out.println("Sorted list of numbers");\r\n \r\n for (c = 0; c < n; c++) \r\n
System.out.println(array[c]);\r\n }\r\n}'
How can I get the code as it is in original file?
Thanks
Abhinav