Javascript - remove a string in the middle of a string

Question

Thank you everyone for your great help !

Sorry, I have to edit my question.

What if the "-6.7.8" is a random string that starts with "-" and has two "." between random numbers? such as "-609.7892.805667"?

===============

I am new to JavaScript, could someone help me for the following question?

I have a string AB.CD.1.23.3-609.7.8.EF.HI

I would like to break it into two strings: AB.CD.1.2.3.EF.HI (remove -609.7.8 in the middle) and AB.CD.6.7.8.EF.HI (remove 1.23.3- in the middle).

Is there an easy way to do it?

Thank you very much!

you are also removing the trailing digits in 1.2 3 .3 and 6 09 .7.8. Is that correct? — C.B.
– C.B., Commented Jan 23, 2014 at 15:41
Either there is a typo or your results are wrong. I get AB.CD.1.23.3.EF.HI and AB.CD.609.7.8.EF.HI — Danny
– Danny, Commented Jan 23, 2014 at 15:46

Danny · Accepted Answer · 2014-01-23 15:50:12Z

1

var s = "AB.CD.1.23.3-609.7.8.EF.HI";
var a = s.replace("-609.7.8","");
var b = s.replace("1.23.3-","");
console.log(a); //AB.CD.1.23.3.EF.HI
console.log(b); //AB.CD.609.7.8.EF.HI

answered Jan 23, 2014 at 15:50

Danny

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user1731872 · Accepted Answer · 2014-01-23 15:48:11Z

0

You could use str.replace(); var str = "AB.CD.1.2.3-6.7.8.EF.HI"; var str1 = str.replace("-6.7.8",""); // should return "AB.CD.1.2.3.EF.HI" var str2 = str.replace("1.2.3-",""); // should return "AB.CD.6.7.8.EF.HI"

answered Jan 23, 2014 at 15:48

user1731872

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bdavidxyz · Accepted Answer · 2014-01-23 15:48:39Z

0

Use split() in String.prototype.split

var myString = "AB.CD.1.23.3-609.7.8.EF.HI";
var splits1 = myString.split("-609.7.8");
console.log(splits1);
var splits2 = myString.split("1.23.3-");
console.log(splits2);

answered Jan 23, 2014 at 15:48

bdavidxyz

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Matt Clarkson · Accepted Answer · 2014-01-23 15:53:31Z

0

With regular expressions:

s = 'AB.CD.1.23.3-609.7.8.EF.HI'
var re = /([A-Z]+\.[A-Z]+)\.([0-9]+\.[0-9]+.[0-9]+)-([0-9]+\.[0-9]+.[0-9]+)\.([A-Z]+\.[A-Z]+)/
matches = re.exec(s)
a = matches[1] + '.' + matches[2] + '.' + matches[4] // "AB.CD.1.23.3.EF.HI"
b = matches[1] + '.' + matches[3] + '.' + matches[4] // "AB.CD.609.7.8.EF.HI"

answered Jan 23, 2014 at 15:53

Matt Clarkson

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