Syntax error on simple IF. [duplicate]

Question

Before you ask, I did look at other answers and questions they all seem to be the same and yes I did add it but still nothing. Okay, so I have a program with a menu and at the menu choice it keeps coming up with syntax error at the ":" colon, help please I have tried everything. Here's the code :

def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = (input("What would you like to search?: ")
            if menu == '1':
                print("You chose Class")
                list = ['Assault', 'Engineer', 'Support', 'Recon']
                from random import choice
                print(choice(list))

            elif menu == '2'
                print("nice")

Error = Syntax error then it highlights the ":" in red.

Your indentation looks wrong, why is the if indented more than the previous line? — Mat
– Mat, Commented Nov 10, 2013 at 16:42
You have an extra ( before input. Also, are you using Pythong 2.x or 3.x? — ratatoskr
– ratatoskr, Commented Nov 10, 2013 at 16:43

aIKid · Accepted Answer · 2013-11-10 16:48:24Z

0

You're missing a closing parentheses on your input function, which you don't need at all.

menu = input("What would you like to search?: ")

Full fixed code:

def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = input("What would you like to search?: ")
    if menu == '1':
        print("You chose Class")
        list = ['Assault', 'Engineer', 'Support', 'Recon']
        from random import choice
        print(choice(list))

    elif menu == '2':
        print("nice")

edited Nov 10, 2013 at 16:48

answered Nov 10, 2013 at 16:43

aIKid

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Comments

shad0w_wa1k3r · Accepted Answer · 2013-11-10 16:44:09Z

0

The input() has an unnecessary paranthesis in the beginning.
The if statement is wrongly indented more.
The elif doesn't have a :
Imports must be made at the beginning.

Correct code

from random import choice
def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = input("What would you like to search?: ")
    if menu == '1':
        print("You chose Class")
        list = ['Assault', 'Engineer', 'Support', 'Recon']
        print(choice(list))

    elif menu == '2':
        print("nice")

answered Nov 10, 2013 at 16:44

shad0w_wa1k3r

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