Stripping off urls' in a java string

Question

I've tried this for a couple of hours and wasn't able to do this correctly; so I figured I'd post it here. Here's my problem.

Given a string in java :

"this is <a href='something'>one \nlink</a> some text <a href='fubar'>two \nlink</a> extra text"

Now i want to strip out the link tag from this string using regular expressions - so the resulting string should look like :

"this is one \nlink some text two \nlink extra text"

I've tried all kind of things in java regular expressions; capturing groups, greedy qualifiers - you name it, and still can't get it to work quite right. If there's only one link tag in the string, I can get it work easily. However my string can have multiple url's embedded in it which is what's preventing my expression to work. Here's what i have so far - (?s).*(<a.*>(.*)</a>).*

Note that the string inside the link can be of variable length, which is why i have the .* in the expression.

If somebody can give me a regular expression that'll work, I'll be extremely grateful. Short of looping through each character and removing the links i can't find a solution.

If you want to follow standards, (X)HTML attributes are surrounded by double quotes ("), not single quotes ('). — Paul Lammertsma
– Paul Lammertsma, Commented Dec 29, 2009 at 20:24

Nathan Hughes · Accepted Answer · 2009-12-29 20:33:27Z

3

Sometimes it's easier to do it in 2 steps:

s = "this is <a href='something'>one \nlink</a> some text <a href='fubar'>two \nlink</a> extra text"
s.replaceAll("<a[^>]*>", "").replaceAll("</a>", "")
Result: "this is one \nlink some text two \nlink extra text"

answered Dec 29, 2009 at 20:33

Nathan Hughes

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Daniel Rhoden · Accepted Answer · 2009-12-29 20:28:52Z

2

Here's the way I usually match tags:

<a .*?>|</a>

and replace with an empty string.

Alternatively, instead of removing the tag, you might comment it out. The match pattern would be the same, but the replacement would be:

<!--\0-->

or

<!--$0-->

If you want to have a reference to the anchor text, use this match pattern:

<a .*?>(.*?)</a>

and the replacement would be an index of 1 instead of 0.

Note: Sometimes you have to use programming-language specific flags to allow regex to match across lines (multi-line pattern match). Here's a Java Example

Pattern aPattern = Pattern.compile(regexString,Pattern.MULTILINE);

edited Dec 29, 2009 at 20:28

answered Dec 29, 2009 at 20:21

Daniel Rhoden

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James Keesey · Accepted Answer · 2009-12-29 20:06:13Z

1

Off the top of my head

"<a [^>]*>|</a>"

answered Dec 29, 2009 at 20:06

James Keesey

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