Python: Read next line in a file in one simple line of code

Question

As the title says, I would like to use a simple command to make Python read the next line of a text file.
For example something like this:

users = open("C:\\Users\\Tharix\\Desktop\\test.txt",mode="r")
line = test.readline(20)
print(line)
line.next() #Or something similar
print(line)

(PS: I don't know this helps, but I'm using version 3.3.2 of Python)

Ashwini Chaudhary · Accepted Answer · 2013-09-21 19:01:14Z

5

Simply iterate over the file object:

with open("C:\\Users\\Tharix\\Desktop\\test.txt", mode="r") as users:
    for line in users:
       print(line)

Note that iter.next() has been renamed to iter.__next__() in py3.x, or better use next(iter).(This works in both py2.7, py3.x)

edited Sep 21, 2013 at 19:01

answered Sep 21, 2013 at 18:54

Ashwini Chaudhary

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4 Comments

AJMansfield Over a year ago

And one more thing, is that if you are going to try calling FooIterator.__next__() yourself, you actually need to write it as FooIterator._FooIterator_next__(), because of the way the name mangling invoked by the __ prefix works.

josh Over a year ago

@hcwhsa That's not what I exactly meant, Edit: Nevermind, got it

Veedrac Over a year ago

a = iter("hello"); a.__next__() works for me. Name mangling is only when the attribute starts with __ and doesn't end with it.

Veedrac Over a year ago

@user2802035 Use line = next(users) (which is what hcwhsa said).

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