How to fill an array with values in a for loop

Question

I have to submit a script which adds two values within an for loop and puts every result in an array. I put together a script (which is not working) but I cannot figure out how to get it started.

#!/bin/sh

val1=$1
val2=$2
for i in 10
    do
        ${array[i]}='expr $val1+$val2'
        $val1++
    done    
echo ${array[@]}

konsolebox · Accepted Answer · 2013-09-09 12:35:06Z

5

Perhaps you mean this?

val1=$1
val2=$2
for i in {1..10}; do
    array[i]=$(( val1 + val2 ))
    (( ++val1 ))
done    
echo "${array[@]}"

If you bash doesn't support {x..y}, use this format:

for (( i = 1; i <= 10; ++i )); do

Also simpler form of

    array[i]=$(( val1 + val2 ))
    (( ++val1 ))

Is

    (( array[i] = val1 + val2, ++val1 )) ## val1++ + val2 looks dirty

answered Sep 9, 2013 at 12:35

konsolebox

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1 Comment

Ed Morton Over a year ago

And please let us know what grade you get after you submit it :-).

Community · Accepted Answer · 2017-05-23 12:24:23Z

2

konsolebox's answer is right, but here are some alternatives:

val1=$1
val2=$2
for i in {0..9}; do
    (( array[i]=val1 + val2 + i ))
done
echo "${array[@]}"

val1=$1
val2=$2
for (( i=val1 + val2; i < val1 + val2 + 10; i++ )); do
    array+=("$i")
done
echo "${array[@]}"

edited May 23, 2017 at 12:24

CommunityBot

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answered Sep 9, 2013 at 18:07

Aleks-Daniel Jakimenko-A.

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