Bash - arrays in a for loop

Question

I'm trying to make a shell script but I'm stuck.

This doesn't work and I don't know why.

a=( "1" "2" )
b=( "3" "4" )
c=( "$a" "$b" )

for d in "${c[@]}"; do
    echo "${d[1]}"
done

In bash, array elements must be scalars, i.e., there's no multidimensional array in bash. — 4ae1e1
– 4ae1e1, Commented Dec 26, 2015 at 11:31
Have a look at this one: stackoverflow.com/questions/16487258/… and this one too: stackoverflow.com/questions/11233825/… — Jahid
– Jahid, Commented Dec 26, 2015 at 13:47

Cyrus · Accepted Answer · 2015-12-26 12:15:00Z

2

With bash:

a=( "1" "2" )
b=( "3" "4" )

# concatenate array a and b to new array c
c=( "${a[@]}" "${b[@]}" )

for d in "${c[@]}"; do 
  echo "$d"
done

Output:

answered Dec 26, 2015 at 12:09

Cyrus

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