For loop for an array in bash

Question

If I want to print out the contents from the 13 element till the second last element of an array and I don't know how long the array is, is this how it would be done with BASH?

for array_element in `seq 13 $(({myarray[@]-1))`
do
   echo ${myarray[array_element]}
done

This is one valid way of it. Just change $(({myarray[@]-1)) to $((${#myarray[@]}-1)) — anishsane
– anishsane, Commented Apr 27, 2015 at 9:32

chepner · Accepted Answer · 2015-04-27 12:22:55Z

2

Since you're using bash, don't use seq. Instead, use a C-style for loop.

for ((i=13; i < ${#myarray[@]} - 1; i++)); do
    echo ${myarray[i]}
done

edited Apr 27, 2015 at 12:22

answered Apr 27, 2015 at 12:16

chepner

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Comments

Leonard Burtscher · Accepted Answer · 2015-04-27 09:50:47Z

0

You could do it like this:

    for array_element in `seq $((${#myarray[@]}-1))`
    do
       echo ${myarray[$((array_element-1))]}
    done

answered Apr 27, 2015 at 9:50

Leonard Burtscher

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