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Of course, if possible, without any VBScript-like scripts.

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Lastnico,

Hello, I think I have a solution to your problem. Try the following:

Try this at your command prompt:

C:\> cmd /c exit /b 4

C:\> echo %errorlevel%

The result should be 4.

Here is a screen shot of my result:

Result of Code http://img691.imageshack.us/img691/7473/cmdc.jpg

I hope this helps,

Thanks!

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The exit code is stored in the ERRORLEVEL environment variable:

echo %ERRORLEVEL%

To test it you can create a simple batch file that exits using the exit code passed as parameter:

exit_code.bat

@exit /b %1

Testing:

> exit_code.bat 8
> echo %ERRORLEVEL%
8
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6 Comments

my command line is always returning 9009 error code. Do you know why?
This doesn't seem to work for me.
It's just a typo in his code, it's supposed to be %1 instead of %i, no reason to downvote.
I can't un-downvote until the answer is edited. Kaniabi, if you edit your answer to correct, I should be able to un-downvote. Thanks!
Ops. Typo fixed. Thanks all for the feedback.
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