C++ constexpr function-definition is not allowed

Question

I'm trying to learn C++, specifically C++11 since we mostly study C, and I've ran into an error while trying to test what "constexpr" can do.

Test 1:

#include <iostream>;

using namespace std;

int main()
{
    int x = 3;
    int y = 4;
    constexpr int Sum(int a, int b) {return a + b;}
    cout << Sum(x,y);
    return 0;
}

Test 2:

#include <iostream>;

using namespace std;

int main()
{
    int x = 3;
    int y = 4;
    constexpr int Sum() {return 3+4;}
    cout << Sum();
    return 0;
}

On both cases, it gave me the following errors:

E:\C++\Lesson1\main.cpp|9|error: a function-definition is not allowed here before '{' token| E:\C++\Lesson1\main.cpp|10|error: 'Sum' was not declared in this scope|

Am I doing something wrong or I have to do something to the compiler? (Using Code Blocks and I have C++11 enabled.

Does this answer your question? Why are local function definitions illegal in C++? — Jan Schultke
– Jan Schultke, Commented Sep 4, 2023 at 10:27

Nicola Musatti · Accepted Answer · 2013-06-15 21:26:18Z

3

Try moving your constexpr function definition outside of main().

answered Jun 15, 2013 at 21:26

Nicola Musatti

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Comments

built1n · Accepted Answer · 2013-06-15 21:27:06Z

2

Your problem

You put a semicolon after a preprocessor directive (#include). You should never do that, unless #define-ing something. This is making the compiler go nuts. Also, in addition to that, you cannot define a function within a function. You must define it outside, in global or class scope.

Solution

Remove the semicolon behind #include <iostream>. Move the constexpr definition above main().

answered Jun 15, 2013 at 21:27

built1n

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1 Comment

Lord Zsolt Over a year ago

Oh yeah, that was a mistake on my part.

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