8

I have a class defined like this:

[XmlRoot(ElementName="request")]
public class Request
{
    #region Attributes
    [XmlAttribute(AttributeName = "version")]
    public string Version
    {
        get
        {
            return "1.0";
        }
    }

    [XmlAttribute(AttributeName = "action")]
    public EAction Action
    {
        get;
        set;
    }
    #endregion

But when I serialize it, "version" doesn't show up in the attribute (while "action" does).

What's going wrong?

2 Answers 2

4

XmlSerializer is going to ignore Version because it doesn't have a set, so there is no way it can attempt to ever deserialize it. Perhaps instead:

[XmlAttribute(AttributeName = "version")]
public string Version {get;set;}

public Request() { Version = "1.0"; }

which will have the same effect overall (although will require an extra string field per-instance - although all of the "1.0" values will be the same actual string instance, via interning), but will allow you to capture properly the version of data you are deserializing.

If you don't care about deserialization, then maybe just add a no-op set:

[XmlAttribute(AttributeName = "version")]
public string Version
{
    get { return "1.0"; }
    set { }
}
Sign up to request clarification or add additional context in comments.

Comments

2

You have to set an empty setter. It's a limitation of XmlAttribute.

[XmlRoot(ElementName="request")]
public class Request
{
    #region Attributes
    [XmlAttribute(AttributeName = "version")]
    public string Version
    {
        get
        {
            return "1.0";
        }
        set{}
    }

    [XmlAttribute(AttributeName = "action")]
    public EAction Action
    {
        get;
        set;
    }
    #endregion

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.