How to get node's value of an XML in Python?

Question

suppose i have an xml file:

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
  <quarkSettings>
    <UpdatePath></UpdatePath>
    <Version>Development</Version>
    <Project>ABC</Project>
  </quarkSettings>
</configuration>

now i want get Project's value. I have written following code:

        import xml.etree.ElementTree as ET
        doc1 = ET.parse("Configuration.xml")
        for e in doc1.find("Project"):
                project =e.text

but it doesn't give the value.

jamylak · Accepted Answer · 2013-04-30 07:43:22Z

2

i got the answer:

import xml.etree.ElementTree as ET            
doc1 = ET.parse(get_path_for_config_Quark_Release)
root = doc1.getroot()
for element in root.findall("quarkSettings"):
    project = element.find("Project").text

edited Apr 30, 2013 at 7:43

jamylak

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answered Apr 30, 2013 at 6:52

bappa147

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